(64x^2-40x+25)/(512x^3+125)

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Solution for (64x^2-40x+25)/(512x^3+125) equation: 


D( x )

512*x^3+125 = 0

512*x^3+125 = 0

512*x^3+125 = 0

512*x^3 = -125 // : 512

x^3 = -125/512

x^3 = -125/512 // ^ 1/3

x = -5/8

x in (-oo:-5/8) U (-5/8:+oo)

(64*x^2-(40*x)+25)/(512*x^3+125) = 0

(64*x^2-40*x+25)/(512*x^3+125) = 0

64*x^2-40*x+25 = 0

64*x^2-40*x+25 = 0

DELTA = (-40)^2-(4*25*64)

DELTA = -4800

DELTA < 0

1 = 0

1/(512*x^3+125) = 0

x belongs to the empty set

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